String Manipulation - please help

[Kasito]

I have a code and dont know how to include a variable name "asubject1" in a TextFile.ReadToString address. The variable has the subject name which determines the location.

Example Code:

if asubject1 then

Qans2 = TextFile.ReadToString("AutoPlay\\Docs\\pool\\asubj ect1\\q2011\\2ans.txt");

if Qans2 == "1" then Image.Load("Ans1", "AutoPlay\\Images\\tick.png");

elseif Qans2 == "2" then Image.Load("Ans2", "AutoPlay\\Images\\tick.png");

elseif Qans2 == "3" then Image.Load("Ans3", "AutoPlay\\Images\\tick.png");

elseif Qans2 == "4" then Image.Load("Ans4", "AutoPlay\\Images\\tick.png");
end
end

Please i need help with example. Thanks.

[herrin]

Compare = String.CompareNoCase(sQuans, "1");
if (Compare == 1) then

[Kasito]

herrin, sincerely i dont seem to understand what you mean i should copare. can you elaborate a little on the example?

Compare = String.CompareNoCase(sQuans, "1"); if (Compare == 1) then

Note that my issue is "asubject1 variable, not the Qans as you referred.

[Kasito]

I mean this line of code:

Qans2 = TextFile.ReadToString("AutoPlay\\Docs\\pool\\asubj ect1\\q2011\\2ans.txt");


This is what im trying to do:

Qans2 = TextFile.ReadToString("AutoPlay\\Docs\\pool\", asubject1.. "\\q2011\\2ans.txt");


I Mean, how do i do the above properly?

[Imagine Programming]

Qans2 = TextFile.ReadToString("AutoPlay\\Docs\\pool\[COLOR=#FF0000][B]\[/B][/COLOR]" .. asubject1.. "\\q2011\\2ans.txt");

- Did you forget a backslash there? Without two backslashes, you'll be escaping the next character instead. I later noticed a comma in stead of the concatenation operator as well

[BioHazard]

Something like this, you mean?

Qans2 = TextFile.ReadToString("AutoPlay\\Docs\\pool\\asubject1\\q2011\\2ans.txt"); 
Image.Load("Ans"..Qans2, "AutoPlay\\Images\\tick.png");

It's hard to discern exactly what you're after - but try my example, attached.

[Kasito]

Qans2 = TextFile.ReadToString("AutoPlay\\Docs\\pool\[COLOR=#FF0000][B]\[/B][/COLOR]" .. asubject1.. "\\q2011\\2ans.txt");

- Did you forget a backslash there? Without two backslashes, you'll be escaping the next character instead. I later noticed a comma in stead of the concatenation operator as well

Thanks a million bro, you have solved my problem and have well implemented it. It works great!

I actually forgot the 1 back slash and have always think a comma in between variables but you have cleared me. Thanks again.

[herrin]

I doubt the problem was the backslash.........

[ATTACH]n303952[/ATTACH]

[Kasito]

herrin, your code is now downloadable so how can i confirm your doubt? please correct the issue so we can look at it.

[herrin]

Thanks a million bro, you have solved my problem and have well implemented it. It works great!
I actually forgot the 1 back slash and have always think a comma in between variables but you have cleared me. Thanks again.

if you have solved the problem what do you need to know if my doubt was founded?