Seconds to Milliseconds

[milano88]

hi all,

function AB(sSeconds)
	local nSeconds = String.ToNumber(sSeconds)
	if nSeconds == 0 then
		
		return "00:00.00";
	else
		local nMins = string.format("%02.f", Math.Floor(nSeconds/60));
		local nSecs = string.format("%02.f", Math.Floor(nSeconds - nMins *60));
		local nMilliSec = string.format("%02.f", Math.Floor(nSeconds - (nMins *60000) - (nSecs *1000)));
		return nMins..":"..nSecs.."."..nMilliSec
	end
end

how to convert seconds to milliseconds in functions AB ?
for example :
01:03.45 --->>> 01:03.99 = 01:04.00
thanks advance

[jassing]

I don't follow your 01:03.45 --> 01:03.99
to convert seconds to milliseconds, you divide seconds by 1000

[milano88]

function millis_to_time(millis)
       local retm=0;
       local rets=0;
       while(millis>(60*1000)-1) do
              millis=millis-(60*1000);
              retm=retm+1;
       end
       while(millis>999) do
              millis=millis-1000;
              rets=rets+1;
       end
       return retm..":"..rets.."."..millis
end

[Imagine Programming]

I don't follow your 01:03.45 --> 01:03.99
to convert seconds to milliseconds, you divide seconds by 1000

You mean multiply seconds by 1000? Considering 1000ms = 1sec

[milano88]

yes Imagine Programming only instead of 1000 to 100 01,02...100 = 1 seconds

[RaMb]

function millis_to_time(millis)
       local retm=0;
       local rets=0;
       while(millis>(60*1000)-1) do
              millis=millis-(60*1000);
              retm=retm+1;
       end
       while(millis>999) do
              millis=millis-1000;
              rets=rets+1;
       end
       return retm..":"..rets.."."..millis
end

yes Imagine Programming only instead of 1000 to 100 01,02...100 = 1 seconds

function convert(msec)
    ms = Math.Mod(msec,1000)
    sec = Math.Floor(Math.Mod(msec/1000,60))
    min = Math.Floor(msec/60000)
    return min..":"..sec.."."..ms
end 

- J

[milano88]

function convert(msec)
    ms = Math.Mod(msec,1000)
    sec = Math.Floor(Math.Mod(msec/1000,60))
    min = Math.Floor(msec/60000)
    return min..":"..sec.."."..ms
end 

- J

I want something like this but does not work

function convert(msec)
    local nMins = string.format("%02.f", Math.Floor(msec/60));
    local nSecs = string.format("%02.f", Math.Floor(msec - nMins *60));
    local nMilliSec = string.format("%02.f", (nSecs/Math.Mod(msec, 1000))*100);
    return nMins..":"..nSecs.."."..nMilliSec
end 

[RaMb]

I want something like this but does not work

function convert(msec)
    local nMins = string.format("%02.f", Math.Floor(msec/60));
    local nSecs = string.format("%02.f", Math.Floor(msec - nMins *60));
    local nMilliSec = string.format("%02.f", (nSecs/Math.Mod(msec, 1000))*100);
    return nMins..":"..nSecs.."."..nMilliSec
end 

function convert(msec)
ms = string.format("%02d",Math.Mod(msec,1000))
sec = string.format("%02d",Math.Floor(Math.Mod(msec/1000,60)))
min = Math.Floor(msec/60000)
return min..":"..sec.."."..ms
end

[milano88]

function convert(msec)
ms = string.format("%02d",Math.Mod(msec,1000))
sec = string.format("%02d",Math.Floor(Math.Mod(msec/1000,60)))
min = Math.Floor(msec/60000)
return min..":"..sec.."."..ms
end

many thanks for your help RaMb can not explain it



must be like that because i make a lyrics maker, thank you very much indeed