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reg entry on Windows 7 64-bit

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  • klabautermann
    replied
    Hello Eagle,
    Thanks for the tip!
    Clear advantage is the one who can read!

    Leave a comment:


  • Eagle
    replied
    Read the AMS help on REG_BINARY properly , you will see why ....

    Leave a comment:


  • klabautermann
    replied
    Hello Samio,
    Thanks for pointing out because it was a direct hit!

    But Now that I have eliminated the one I have the next problem and wonder why only the first value is entered !?

    Registry.SetValue (HKEY_LOCAL_MACHINE, "System\\CurrentControlSet\\MultiKey\\dumps\\00007 50A", "hlkMemory", "4c 45,58,2d,43,4f,4d,20,47,6d,62.48,20,20,20,20,20,20 ,20,20,33 "REG_BINARY);

    4c,45,58,2d,43,4f,4d,20,47,6d,62.48,20,20,20,20,20 ,20,20,20,33 = 4c >>> why is only the 4c worth playing?

    Leave a comment:


  • Samio
    replied
    you must set your value with decimal format: c84a=51274
    Registry.SetValue (HKEY_LOCAL_MACHINE, "System\\CurrentControlSet\\MultiKey\\Dumps\\0 0007 50A", "Seed3", "51274" REG_DWORD);

    Leave a comment:


  • klabautermann
    started a topic reg entry on Windows 7 64-bit

    reg entry on Windows 7 64-bit

    Why are the values for the registry entries in Windows 7 not registered?

    here's an example:
    Registry.SetValue (HKEY_LOCAL_MACHINE, "System\\CurrentControlSet\\MultiKey\\Dumps\\00007 50A", "Seed3", "c84a" REG_DWORD);

    c84a = 0 >>> Why is the entry 0 ???
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